The Length Of Rectangle Is 8 Meters More Than Twice Its Width. The Perimeter Is 112 Meters. Find Its Area

the length of rectangle is 8 meters more than twice its width. the perimeter is 112 meters. find its area

Answer:

640 square meters

Computation:

Representation

$\left\begin{array}{ccc}width\to&x\\length\to&2x+8\end{array}\right$

Solving for the width.

$2(length)+2(width)=perimeter\\2(2x+8)+2(x)=112\\4x+16+2x=112\\6x=112-16\\6x=96\\x=96/6=16$

Solving for the length.

$2x+8=2(16)+8=32+8=40$

Solving for the area.

$A=length*width=40\:m*16\:m=640\:m^{2}$

Sharedada